Strategy Views’ Post

Day 273 & Two Marks There has been an interesting discussion on the Queens, by LinkedIn game - what are the minimal number of marks you need to make to produce a correct solution of the game. The question can be tightened up a bit. Turn on Auto Xes in the options. Count a mark as either as "X" or a "Queen". Make no errors or undoes. Does every game after a minimal, say less than 3, marks turn into a game that solves itself? A game solves itself when: 1) Auto X's are on, 2) there is always just one colour left after each mark, until the game is solved. In Game 273, can you guess how many colours or squares that you need to place before the game solves itself? Here is an example - two marks, one X and one Queen to start the game. Each mark, after the first two, is forced. There is at least one colour which only has 1 square left. And this is true until the game is solved. Can this game be done with less marks? (Probably not.) If not, how do you prove this? (Harder question. Working on it.) Here is the movie:

Jeff B.

Software Developer Sr

2mo

... (continued from yesterday's Queens (#272) comments) ... That is a good video, though the text poses a different problem, than I was thinking-of. Different because, to me it isn't clear how a player, without some calculation, would start today's Queens game knowing that there should be an X where you put the initial X, and a queen where you put the initial queen. However, could today's game be self-solving with any less than 2 marks? I say no, because just less than 2 is 1, and my 1 mark would be a queen, and after trying all 8 of those queens, none lead to a self-solved puzzle.

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